From 00c9176dee8d64ee93fbe0b23d62bdd8f2090329 Mon Sep 17 00:00:00 2001
From: Andrea Mazzoleni
If Disk 1 is destroyed, the system solves the remaining equation:
- [?] + 15 = 25.
- The system identifies the missing value (10) and restores it to a new disk.
+ [?] + 3 = 8.
+ The system identifies the missing value (5) and restores it to a new disk.
- Limitation: Single parity can only solve for one unknown variable. If two disks fail simultaneously, the mathematical equation becomes unsolvable (e.g., X + Y = 25 has too many possibilities).
+ Limitation: Single parity can only solve for one unknown variable. If two disks fail simultaneously, the mathematical equation becomes unsolvable (e.g., X + Y = 8 has too many possibilities).