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Default to 8 MiB of blocks for the IO cache

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This commit is contained in:
Andrea Mazzoleni 2016-01-20 22:03:14 +01:00
parent e2c4399e28
commit 377352e64f
1 changed files with 11 additions and 4 deletions
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15
cmdline/io.c
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@ -56,10 +56,17 @@ void io_init(struct snapraid_io* io, struct snapraid_state* state,
pthread_cond_init(&io->write_sched, 0);
io->state = state;
if (io_cache == 0)
io->io_max = 32;
else
if (io_cache == 0) {
/* default is 8 MiB of cache */
/* this seems to be a good tradeoff between speed and memory usage */
io->io_max = 8 * 1024 * 1024 / state->block_size;
if (io->io_max < IO_MIN)
io->io_max = IO_MIN;
if (io->io_max > IO_MAX)
io->io_max = IO_MAX;
} else {
io->io_max = io_cache;
}
assert(io->io_max >= IO_MIN && io->io_max <= IO_MAX);
@ -72,7 +79,7 @@ void io_init(struct snapraid_io* io, struct snapraid_state* state,
allocated += state->block_size * buffer_max;
}
msg_progress("Using %u MiB of memory for the IO cache.\n", (unsigned)(allocated / MEBI));
msg_progress("Using %u MiB of memory for %u blocks of IO cache.\n", (unsigned)(allocated / MEBI), io->io_max);
if (parity_writer) {
io->reader_max = handle_max;