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Summarizing Channel size on Channels page, rather than info age.

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Roland 2023-05-10 22:59:16 -06:00
parent f079263fad
commit 7c5caf1dfd
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2 changed files with 10 additions and 14 deletions
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17
modules/videos/channel/lib.py
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@ -26,20 +26,17 @@ async def get_minimal_channels() -> List[dict]:
# Get all channels, even if they don't have videos.
stmt = '''
SELECT
c.id, name, directory, url, download_frequency, info_date,
(select next_download from download d where d.url=c.url) AS next_download
c.id, name, directory, c.url, download_frequency,
COUNT(v.id) as video_count,
SUM(fg.size)::BIGINT AS size
FROM
channel AS c
ORDER BY LOWER(name)
LEFT JOIN video v on c.id = v.channel_id
LEFT JOIN file_group fg on fg.id = v.file_group_id
GROUP BY 1, 2, 3, 4, 5
'''
curs.execute(stmt)
channels = list(map(dict, curs.fetchall()))
video_counts = await get_channels_video_count()
for channel in channels:
channel_id = channel['id']
channel['video_count'] = video_counts[channel_id]
channels = sorted([dict(i) for i in curs.fetchall()], key=lambda i: i['name'].lower())
return channels